Practice Free 300-410 Exam Online Questions
Refer to the exhibit.
Which action resolves the adjacency issue?
- A . Match the hello interval timers.
- B . Configure the same EIGRP process IDs.
- C . Match the authentication keys.
- D . Configure the same autonomous system numbers.
D
Explanation:
EIGRP does not have process ID as it uses Autonomous System (AS) numbers only.
This is not an authentication problem or we would see this error from the debug:
EIGRP: Ethernet0/0: ignored packet from 10.1.1.3, opcode = 1 (missing authentication or key-chain missing)
If the AS numbers between two routers are different then the neighbor relationship cannot be formed.
After some changes in the routing policy, it is noticed that the router in AS 45123 is being used as a transit AS router for several service provides.
Which configuration ensures that the branch router in AS 45123 advertises only the local networks to all SP neighbors?
A)
B)
C)
D)
- A . Option A
- B . Option B
- C . Option C
- D . Option D
D
Explanation:
By default BGP advertises all prefixes to external BGP neighbors. This means that if you are multi-homed (connected to two or more ISPs) then you might become a transit AS.
For example, ISP 2 in AS 200 can send traffic to your router in AS 100 to reach ISP 3 in AS 300 because you advertised prefixes in ISP 3 to ISP 2.
This is what will be seen in the BGP routing table of ISP1:
Refer to the exhibit.
The route to 192 168 200 0 is flapping between R1 and R2.
Which set of configuration changes resolves the flapping route?
- A . Option A
- B . Option B
- C . Option C
- D . Option D
When provisioning a device in Cisco DNA Center, the engineer sees the error message “Cannot select the device. Not compatible with template”.
What is the reason for the error?
- A . The template has an incorrect configuration.
- B . The software version of the template is different from the software version of the device.
- C . The changes to the template were not committed.
- D . The tag that was used to filter the templates does not match the device tag.
D
Explanation:
If you use tags to filter the templates, you must apply the same tags to the device to which you want to apply the templates. Otherwise, you get the following error during provisioning: DCannot select the device. Not compatible with template.‖
Reference: https://www.cisco.com/c/en/us/td/docs/cloud-systems-management/network-automation-and-management/dna-center/1-2-10/user_guide/b_cisco_dna_center_ug_1_2_10/b_dnac_ug_1_2_10_chapter_0111.html
What does the MP-BGP OPEN message contain?
- A . MPLS labels and the IP address of the router that receives the message
- B . the version number and the AS number to which the router belongs
- C . IP routing information and the AS number to which the router belongs
- D . NLRI, path attributes, and IP addresses of the sending and receiving routers
Refer to the exhibit.
R2 has two paths to reach 192.168.13.0/24. but traffic is sent only through R3.
Which action allows traffic to use both paths?
- A . Configure the bandwidth 2000 command under interface FastEthernet0/0 on R2.
- B . Configure the variance 4 command under the EIGRP process on R2.
- C . Configure the delay 1 command under interface FastEthernet0/0 on R2.
- D . Configure the variance 2 command under the EIGRP process on R2
B
Explanation:
From the output of the “show ip eigrp topology …” command, we notice network 192.168.13.0/24 was learned via two routes:
+ From 192.168.23.3 (R3) with FD = 1075200 and AD = 281600
+ From 192.168.12.1 (R1) with FD = 2611200 and AD = 281600
From the output of the “show ip route …” command, we learned that the best (and chosen) path is via 192.168.23.3 (R3).
To use both paths (called unequal cost load balancing) with EIGRP, the second path via R1 must satisfy the feasibility condition. The feasibility condition states that, the Advertised Distance (AD) of a route must be lower than the feasible distance of the current successor route.
In this case, the second path satisfies the feasible condition as its AD (281600) is smaller than the FD (1075200) of the best path. Therefore we can configure loadbalancing with “variance” command.
In other words, EIGRP will install all paths with metric < variance * best_metric into the local routing table, provided that it meets the feasibility condition to preventrouting loop. Therefore we can calculate the variance > metric / best_metric = 2611200 / 1075200 =2.4.
So with a variance greater than 2 (and must be an integer), we can load balance traffic to network 192.168.13.0/24.
Refer to the exhibit.
Gateway-Router# show ipv6 access-list
IPv6 access list Default_Access
permit tcp host 2018:DB1: A: B::1 host 2018:DB1:A:C::1 eq www sequence 10
deny tcp any host 2018:DB1: A:C::1 eq telnet sequence 20
permit tcp host 2018:DB1: A: B::2 host 2018:DB1:A:C::1 eq telnet sequence 30
permit ipv6 2018:DB1: A: B::/64 any sequence 40
PC-2 failed to establish a Telnet connection to the terminal server.
Which configuration resolves the issue?
- A . Gateway-Router(config)#ipv6 access-list Default Access
Gateway-Router(config-ipv6-acl)#sequence 15 permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C. :1 eq telnet - B . Gateway-Router(config)#ipv6 access-list Default Access
Gateway-Router(config-ipv6-acl)#permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet - C . Gateway-Router(config)#ipv6 access-list Default Access
Gateway-Router(config-ipv6-acl)#no sequence 20
Gateway-Router(config-ipv6-acl)#sequence 5 permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet - D . Gateway-Router(config)#fipv6 access-list Default Access
Gateway-Router(confia-ipv6-acl)#sequence 25 permit tcp host 2018:DB1:A:B:2 host 2018:DB1:A:C. :1 eq telnet
A
Explanation:
In fact in this question both answer A and answer C are correct but we believe answer A is the better choice as it only allows PC-2 to telnet to terminal server. All other hosts are refused to telnet to terminal server via sequence 20.
A network administrator is troubleshooting a high utilization issue on the route processor of a router that was reported by NMS The administrator logged into the router to check the control plane policing and observed that the BGP process is dropping a high number of routing packets and causing thousands of routes to recalculate frequently.
Which solution resolves this issue?
- A . Police the cir for BGP, conform-action transmit, and exceed action transmit.
- B . Shape the pir for BGP, conform-action set-prec-transmit, and exceed action set-frde-transmit.
- C . Shape the cir for BGP. conform-action transmit, and exceed action transmit.
- D . Police the pir for BGP, conform-action set-prec-transmit, and exceed action set-clp-transmit.
D
Explanation:
CIR (Committed Information Rate) is the minimum guaranteed traffic delivered in the network.
PIR (Peak Information Rate) is the top bandwidth point of allowed traffic in a non busy times without any guarantee.
+ Policing: is used to control the rate of traffic flowing across an interface. During a bandwidth exceed (crossed the maximum configured rate), the excess traffic is generally dropped or remarked. The result of traffic policing is an output rate that appears as a saw-tooth with crests and troughs. Traffic policing can be applied to inbound and outbound interfaces. Unlike traffic shaping, QoS policing avoids delays due to queuing. Policing is configured in bytes.
+ Shaping: retains excess packets in a queue and then schedules the excess for later transmission over increments of time. When traffic reaches the maximum configured rate, additional packets are queued instead of being dropped to proceed later. Traffic shaping is applicable only on outbound interfaces as buffering and queuing happens only on outbound interfaces. Shaping is configured in bits per second.
Therefore in this case we can only policing, not shaping as traffic shaping is applicable only on outbound interfaces as buffering and queuing happens only on outbound interfaces. Moreover, BGP traffic is not important so we can drop the excess packets without any problems.
And we only policing the PIR traffic so that the route processor is not overwhelmed by BGP calculation.
Note: The “set-prec-transmit” is the same as “transmit” command except it sets the IP Precedence level as well. The “set-clp-transmit” sets the ATM Cell Loss Priority (CLP) bit from 0 to 1 on the ATM cell and transmits the packet.
What are two functions of LDP? (Choose two.)
- A . It is defined in RFC 3038 and 3039.
- B . It requires MPLS Traffic Engineering.
- C . It advertises labels per Forwarding Equivalence Class.
- D . It must use Resource Reservation Protocol.
- E . It uses Forwarding Equivalence Class
C,E
Explanation:
https://www.cisco.com/c/en/us/td/docs/switches/datacenter/sw/5_x/nx-os/mpls/configuration/guide/mpls_cg/mp_mpls_overview.pdf
Refer to the exhibit.
Router R1 peers with two ISPs using static routes to get to the internet. The requirement is that R1 must prefer ISP-A under normal circumstances and failover to ISP-B if the connectivity to ISP-A is lost. The engineer observes that R1 is load balancing traffic across the two ISPs.
Which action resolves the issue by sending traffic to ISP-A only with failover to ISP-B?
- A . Configure OSPF between R1. ISP-A. and ISP-B for dynamic failover if any ISP link to R1 fails
- B . Configure two static routes on R1. one pointing to ISP-A and another pointing to ISP- B with 222 admin distance
- C . Change the bandwidth of the interface on R1 so that interface to ISP-A has a higher value than the interface to ISP-B
- D . Configure two static routes on R1. one pointing to ISP-B with more specific routes and another pointing to ISP-A with summary routes